Saturday, December 13, 2014

Input 2 Binary Strings and Print their Binary Sum

#include

#include

#include

#include

int bin_verify(char []);

void sum(char [], char [], char []);

int main()

    char bin1[33], bin2[33], result[33];

    int len1, len2, check;

    clrscr();

    printf("Enter binary number 1: ");

    scanf("%s", bin1);

    printf("Enter binary number 2: ");

    scanf("%s", bin2);

    check = bin_verify(bin1);

    if (check)

        printf("Invalid binary number %s.\n", bin1);

        exit(0);

    check = bin_verify(bin2);

    if (check)

        printf("Invalid binary number %s.\n", bin2);

        exit(0);

    sum(bin1, bin2, result);

    printf("%s + %s = %s\n", bin1, bin2, result);

    return 0;

int bin_verify(char str[])

    int i;

    for (i = 0; i < strlen(str); i++)

        if ((str[i] - '0' != 1 ) && (str[i] - '0' != 0))

            return 1;

    return 0;

void sum(char bin1[], char bin2[], char result[])

    int i = strlen(bin1) - 1;

    int j = strlen(bin2) - 1;

    int carry = 0, temp, num1, num2;

    while (i > -1 && j > -1)

        num1 = bin1[i] - '0';

        num2 = bin2[j] - '0';

        temp = num1 + num2 + carry;

        if (temp / 2 == 1)

            carry = 1;

            temp %= 2;

        if (i > j)

            result[i + 1] = temp + '0';

            result[strlen(bin1) + 1] = '\0';

        else

            result[j +1] = temp + '0';

            result[strlen(bin2) + 1] = '\0';

        i--;

        j--;

    while (i > -1)

        temp = bin1[i] + carry - '0';

        if (temp / 2 == 1)

            carry = 1;

            temp %= 2;

        result[i + 1] = temp + '0';

        i--;

    while (j > -1)

        temp = bin2[j] + carry - '0';

        if (temp / 2 == 1)

            carry = 1;

            temp %= 2;

        result[j + 1] = temp + '0';

        j--;

    if (carry)

        result[0] = '1';

    else

        result[0] = '0';

 getch();

Output

Enter binary number 1: 0110

Enter binary number 2: 1011

0110 + 1011 = 10001

Input a String with atleast one Number, Print the Square of all the Numbers in a String

#include

#include

#include

#include

#include

struct detail

    int number;

    int square;

};

int update(struct detail [], int, int);

int toint(char []);

int main()

    struct detail s[10];

    char unit[20], string[100];

    char c;

    int num, i, j = 0, count = 0;

    printf("Enter string: ");

    i = 0;

do

        fflush(stdin);

        c = getchar();

        string[i++] = c;

    } while (c != '\n');

    string[i - 1] = '\0';

    printf("The string entered is: %s\n", string);

    for (i = 0; i < strlen(string); i++)

        while (i < strlen(string) && !isspace(string[i]))

            unit[j++] = string[i++];

        if (j != 0)

            unit[j] = '\0';

            num = toint(unit);

            count = update(s, num, count);

            j = 0;

    printf("*****************\nNumber\tSquare\n*****************\n");

    for (i = 0; i < count; i++)

        printf("%d\t   %d\n", s[i].number, s[i].square);

    return 0;

int update(struct detail s[], int num, int count)

    s[count].number = num;

    s[count].square = num * num;

    return (count + 1);

int toint(char str[])

    int len = strlen(str);

    int i, num = 0;

    for (i = 0; i < len; i++)

        num = num + ((str[len - (i + 1)] - '0') * pow(10, i));

   return num;

getch();

Output

Enter string: 1 2 3 4 5

The string entered is: 1 2 3 4 5

*****************

Number    Square

*****************

1      1

2      4

3      9

4      16

5      25