Display the Nodes of a Linked List in Reverse without using
Recursion
#include
#include
#include
struct node
{
int visited;
int a;
struct node *next;
};
void generate(struct node **);
void display(struct node *);
void linear(struct node *);
void delete(struct node **);
int main()
{
struct node *head = NULL;
generate(&head);
printf("\nPrinting the list in linear order\n");
linear(head);
printf("\nPrinting the list in reverse order\n");
display(head);
delete(&head);
return 0;
}
void display(struct node *head)
{
struct node *temp = head, *prev = head;
while (temp->visited == 0)
{
while (temp->next != NULL && temp->next->visited == 0)
{
temp = temp->next;
}
printf("%d ", temp->a);
temp->visited = 1;
temp = head;
}
}
void linear(struct node *head)
{
while (head != NULL)
{
printf("%d ", head->a);
head = head->next;
}
printf("\n");
}
void generate(struct node **head)
{
int num, i;
struct node *temp;
printf("Enter length of list: ");
scanf("%d", &num);
for (i = num; i > 0; i--)
{
temp = (struct node *)malloc(sizeof(struct node));
temp->a = i;
temp->visited = 0;
if (*head == NULL)
{
*head = temp;
(*head)->next = NULL;
}
else
{
temp->next = *head;
*head = temp;
}
}
}
void delete(struct node **head)
{
struct node *temp;
while (*head != NULL)
{
temp = *head;
*head = (*head)->next;
free(temp);
}
}
Output
Enter length of list: 5
Printing the list in linear order
1 2 3 4 5
Printing the list in reverse order
5 4 3 2 1
No comments:
Post a Comment