Search for an Element in the Linked List without using Recursion
#include
#include
#include
struct node
{
int a;
struct node *next;
};
void generate(struct node **, int);
void search(struct node *, int);
void delete(struct node **);
int main()
{
struct node *head = NULL;
int key, num;
clrscr();
printf("Enter the number of nodes: ");
scanf("%d", &num);
printf("\nDisplaying the list\n");
generate(&head, num);
printf("\nEnter key to search: ");
scanf("%d", &key);
search(head, key);
delete(&head);
return 0;
}
void generate(struct node **head, int num)
{
int i;
struct node *temp;
for (i = 0; i < num; i++)
{
temp = (struct node *)malloc(sizeof(struct node));
temp->a = rand() % num;
if (*head == NULL)
{
*head = temp;
temp->next = NULL;
}
else
{
temp->next = *head;
*head = temp;
}
printf("%d ", temp->a);
}
}
void search(struct node *head, int key)
{
while (head != NULL)
{
if (head->a == key)
{
printf("key found\n");
return;
}
head = head->next;
}
printf("Key not found\n");
}
void delete(struct node **head)
{
struct node *temp;
while (*head != NULL)
{
temp = *head;
*head = (*head)->next;
free(temp);
}
}
Output
Enter the number of nodes: 10
Displaying the list
3 6 7 5 3 5 6 2 9 1
Enter key to search: 2
key found
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