Java Better Pro

Parse CSV File using String To kenizer

import java.io.BufferedReader;

import java.io.FileReader;

import java.io.FileWriter;

import java.util.StringTokenizer;

public class ParseCSVFileExample

{

 public static void main(String[] args)

{

 try

{

String strFile = "C:/FileIO/example.csv";

BufferedReader br = new BufferedReader( new FileReader(strFile));

String strLine = "";

StringTokenizer st = null;

int lineNumber = 0, tokenNumber = 0;

while( (strLine = br.readLine()) != null)

{

lineNumber++;

st = new StringTokenizer(strLine, ",");

while(st.hasMoreTokens())

{

tokenNumber++;

System.out.println("Line # " + lineNumber +

", Token # " + tokenNumber

+ ", Token : "+ st.nextToken());

}

tokenNumber = 0;

  }

}

catch(Exception e)

{

System.out.println("Exception while reading csv file: " + e);                  

      }

    }

}

Reverse string by word using String To kenizer

import java.util.StringTokenizer;

public class ReverseLine

{

 public static void main(String[] args)

{

String strLine = "Java Reverse string by word example";

StringTokenizer st = new StringTokenizer(strLine, " ");

String strReversedLine = "";

while(st.hasMoreTokens())

{

strReversedLine = st.nextToken() + " " + strReversedLine;

}

System.out.println("Reversed string by word is : " + strReversedLine);

   }

}

Find Square Root of Big Integer

import java.math.BigDecimal;

import java.math.BigInteger;

import java.math.MathContext;

import java.math.RoundingMode;

public class SquareRootOfBigIntegerExample

{

public static void main(String[] args)

{

SquareRootOfBigIntegerExample SquareRootOfBigIntegerExample = new SquareRootOfBigIntegerExample();

String n = "";

MathContext mc =  new MathContext(0, RoundingMode.DOWN);

mc = MathContext.DECIMAL32;

                  BigInteger my2P100000  = new BigInteger("0");

                  BigInteger two      = new BigInteger("2");

                  BigInteger one      = new BigInteger("1");

my2P100000  = two.shiftLeft(2000 - 1);

System.out.println("2^2000 --  Step 1");

System.out.println("Value of 2^2,000 " + my2P100000  );

System.out.println("");

System.out.println("Finding the Square Root of 2^2000");

String mys =  my2P100000  + "";

n = (mys) ;

int firsttime = 0;

BigDecimal myNumber = new BigDecimal(n);

BigDecimal g = new BigDecimal("1");

BigDecimal my2 = new BigDecimal("2");

BigDecimal epsilon = new BigDecimal("0.0000000001");

        

BigDecimal nByg = myNumber.divide(g, 9, BigDecimal.ROUND_FLOOR);

BigDecimal nBygPlusg = nByg.add(g);

               

BigDecimal nBygPlusgHalf =  nBygPlusg.divide(my2, 9, BigDecimal.ROUND_FLOOR);

BigDecimal  saveg = nBygPlusgHalf;

firsttime = 99;

do

{

g = nBygPlusgHalf;

nByg = myNumber.divide(g, 9, BigDecimal.ROUND_FLOOR);

nBygPlusg = nByg.add(g);

nBygPlusgHalf =  nBygPlusg.divide(my2, 9, BigDecimal.ROUND_FLOOR);

BigDecimal  savegdiff  = saveg.subtract(nBygPlusgHalf);

 if (savegdiff.compareTo(epsilon) == -1 )

{

firsttime = 0;

}

else

{

saveg = nBygPlusgHalf;

}

}

 while (firsttime > 1);

System.out.println("For " + mys + "\nLength: " + mys.length() + "\nThe Square Root is " + saveg);

        }

}