C Combination program

To find equivalent capacitance of Parallel combination of capacitive circuit

#include

#include 

int main()

{

   float c[10], num, Cp = 0;

   int i;

   clrscr();

   printf("Enter the number of Capacitors : ");

   scanf("%f", &num);

   printf("\nEnter Value of Each Capacitor : n");

   for (i = 0; i < num; i++)

   {

      printf("\nC%d : ", i + 1);

      scanf("%f", &c[i]);

   }

   for (i = 0; i < num; i++)

   {

      Cp = Cp + c[i];

   }

   printf("\nEquivalent Parallel Capacitance : %f mFarad", Cp);

   return (0);

}

Output

Enter the number of Capacitors : 3

Enter Value of Each Capacitor :

C1 : 1.2

C2 : 1.3

C3 : 1.4

Equivalent Parallel Capacitance : 3.900000 mFarad

C Program to Find equivalent capacitance of series combination of capacitive circuit

#include

#include 

 int main()

{

   float c[10], num, Cs = 0;

   int i;

   clrscr();

   printf("Enter the number of Capacitors : ");

   scanf("%f", &num);

   printf("\nEnter Value of Each Capacitor : n");

   for (i = 0; i < num; i++)

   {

      printf("\nC%d : ", i + 1);

      scanf("%f", &c[i]);

   }

    for (i = 0; i < num; i++)

   {

      Cs = Cs + (1.0 / c[i]);

   }

   Cs = 1.0 / Cs;

   printf("\nEquivalent Series Capacitance : %f mFarad", Cs);

   return (0);

}

Output

Enter the number of Capacitors : 3

Enter Value of Each Capacitor :

C1 : 1

C2 : 1

C3 : 1

Equivalent Series Capacitance : 0.333333 mFarad

C Program to Find equivalent resistance of Parallel combination of resistive circuits

#include

#include

int main()

{

   int r[10], num, i, Rs = 0;

   printf("Enter the number of Resistances : ");

   scanf("%d", &num);

   printf("\nEnter Value of Each Resistance : n");

   for (i = 0; i < num; i++)

   {

      printf("\n R%d : ", i + 1);

      scanf("%d", &r[i]);

   }

   for (i = 0; i < num; i++)

   {

      Rs = Rs + r[i];

   }

    printf("\nEquivalent Series Resistance : %d Kohm", Rs);

   return (0);

}

Output

Enter the number of Resistances : 3

Enter Value of Each Resistance :

R1 : 4

R2 : 2

R3 : 3

Equivalent Parallel Resistance : 0.923077 Kohm

To find equivalent resistance of series combination of resistive circuits

#include

#include

int main()

{

    int r[10], num, i, Rs = 0;

    printf("Enter the number of Resistances : ");

    scanf("%d", &num);

    printf("\nEnter Value of Each Resistance : n");

    for (i = 0; i < num; i++)

    {

        printf("\nR%d : ", i + 1);

        scanf("%d", &r[i]);

    }

     for (i = 0; i < num; i++)

    {

        Rs = Rs + r[i];

    }

    printf("\nEquivalent Series Resistance : %d Kohm", Rs);

    return (0);

}

Output

Enter the number of Resistances : 5

Enter Value of Each Resistance :

R1 : 3

R2 : 2

R3 : 3

R4 : 2

R5 : 1

Equivalent Series Resistance : 11 Kohm

To find equivalent capacitance of Parallel combination of capacitive circuit

#include

#include

 int main()

{

   float c[10], num, Cp = 0;

   int i;

   clrscr();

   printf("Enter the number of Capacitors : ");

   scanf("%f", &num); 

   printf("\nEnter Value of Each Capacitor : n");

   for (i = 0; i < num; i++)

  {

      printf("\nC%d : ", i + 1);

      scanf("%f", &c[i]);

   }

    for (i = 0; i < num; i++)

   {

      Cp = Cp + c[i];

   }

   printf("\nEquivalent Parallel Capacitance : %f mFarad", Cp);

   return (0);

}

Output

Enter the number of Capacitors : 3

Enter Value of Each Capacitor :

C1 : 1.2

C2 : 1.3

C3 : 1.4

Equivalent Parallel Capacitance : 3.900000 mFarad