C Convert binary pro

C Program to convert the given Binary Number into Decimal

#include 

        #include

void main()

{

int  num, binary_val, decimal_val = 0, base = 1, rem; 

clrscr();

printf("Enter a binary number(1s and 0s) \n");

scanf("%d", &num); 

binary_val = num;

while (num > 0)

{

rem = num % 10;

decimal_val = decimal_val + rem * base;

num = num / 10 ;

base = base * 2;

}

printf("The Binary number is = %d \n", binary_val);

printf("Its decimal equivalent is = %d \n", decimal_val);

getch();

}

Output

Enter a binary number(1s and 0s)

10101001

The Binary number is = 10101001

Its decimal equivalent is = 169S

C Program to Reverse a Given Number

#include 

    #include

void main()

{

long  num, reverse = 0, temp, remainder;

clrscr();

printf("Enter the number\n");

scanf("%ld", &num);

temp = num;

while (num > 0)

{

remainder = num % 10;

reverse = reverse * 10 + remainder;

num /= 10;

}

printf("Given number = %ld\n", temp);

printf("Its reverse is = %ld\n", reverse);

getch();

}

Output

Enter the number

567865

Given number   = 567865

Its reverse is = 568765

C Program to illustrate how User Authentication is done

#include 

#include

void main()

{

   char password[10], username[10], ch;

   int i;

   clrscr();

   printf("Enter User name: ");

   gets(username);

   printf("Enter the password < any 8 characters>: ");

   for (i = 0; i < 8; i++)

   {

            ch = getchar();

            password[i] = ch;

            ch = '*' ;

            printf("%c", ch);

   }

        password[i] = '\0';

   printf("\n Your password is :");

   for (i = 0; i < 8; i++)

   {

            printf("%c", password[i]);

   }

}

Output

Enter User name: rajaraman

Enter the password <any 8 characters>: shashi12

********

Your password is :shashi12

C Program to Convert a Decimal Number to Binary & Count the Number of 1s

#include 

    #include

void main()

{

long num, decimal_num, remainder, base = 1, binary = 0, no_of_1s = 0;

   clrscr();

printf("Enter a decimal integer \n");

scanf("%ld", &num);

decimal_num = num;

while (num > 0)

{

remainder = num % 2;

if (remainder == 1)

{

no_of_1s++;

}

binary = binary + remainder * base;

num = num / 2;

base = base * 10;

}

printf("Input number is = %d\n", decimal_num);

printf("Its binary equivalent is = %ld\n", binary);

printf("No.of 1's in the binary number is = %d\n", no_of_1s);

getch();

}

Output

Enter a decimal integer

134

Input number is = 134

Its binary equivalent is = 10000110

No.of 1's in the binary number is = 3