Display all the Nodes in a c pgm

Display all the Nodes in a Linked List without using Recursion

#include 

#include 

#include 

struct node

{

    int a;

    struct node *next;

};

void generate(struct node **);

void display(struct node*);

void delete(struct node **);

int main()

{

    struct node *head = NULL;

    generate(&head);

    display(head);

    delete(&head);

    return 0;

}

void generate(struct node **head)

{

    int num = 10, i;

    struct node *temp;

    for (i = 0; i < num; i++)

    {

        temp = (struct node *)malloc(sizeof(struct node));

        temp->a = i;

        if (*head == NULL)

        {

            *head = temp;

            (*head)->next = NULL;

        }

        else

        {

            temp->next = *head;

            *head = temp;

        }

    }

}

void display(struct node *head)

{

    while (head != NULL)

    {

        printf("%d   ", head->a);

        head = head->next;

    }

    printf("\n");

}

void delete(struct node **head)

{

    struct node *temp;

    while (*head != NULL)

    {

        temp = *head;

        *head = (*head)->next;

        free(temp);

    }

}

Output

9   8   7   6   5   4   3   2   1   0