Printing Array using
Method
import java.util.ArrayList;
import java.util.Vector;
public class Main
{
public static void main(String[] args)
{
Object testObject = new ArrayList();
displayObjectClass(testObject);
}
public static void displayObjectClass(Object o)
{
if (o instanceof Vector)
System.out.println("Object was an instance
of the class java.util.Vector");
else if (o instanceof ArrayList)
System.out.println("Object was an instance of
the class java.util.ArrayList");
else
System.out.println("Object was an instance of the " + o.getClass());
}
}
Use of break statement
public class Main
{
public static void main(String[] args)
{
int[] intary = { 99,12,22,34,45,67,5678,8990 };
int no = 5678;
int i = 0;
boolean found = false;
for ( ; i < intary.length; i++)
{
if (intary[i] == no)
{
found = true;
break;
}
}
if (found)
{
System.out.println("Found the no: " + no + " at index: " + i);
}
else
{
System.out.println(no + "not found in the array");
}
}
}
Use of continue
public class Main
{
public static void main(String[] args)
{
StringBuffer searchstr = new StringBuffer("hello how are you. ");
int length = searchstr.length();
int count = 0;
for (int i = 0; i 7lt; length; i++)
{
if (searchstr.charAt(i) != 'h')
continue;
count++;
searchstr.setCharAt(i, 'h');
}
System.out.println("Found " + count + " h's in the string.");
System.out.println(searchstr);
}
}
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