Display Pascal triangle

Display Pascal triangle

#include 

#include 

void main()

{

    int array[15][15], i, j, rows, num = 25, k;

    clrscr();

    printf("\n enter the number of rows:");

    scanf("%d", &rows);

    for (i = 0; i < rows; i++)

    {

        for (k = num - 2 * i; k >= 0; k--)

            printf(" ");

                for (j = 0; j <= i; j++)

                {

                if (j == 0 || i == j)

                        {

                    array[i][j] = 1;

                }

                else

                {

                    array[i][j] = array[i - 1][j - 1] + array[i - 1][j];

                        }

                        printf("%4d", array[i][j]);

            }

            printf("\n");

    } 

   getch();

}

Output

enter the number of rows:2

                             1

                           1   1

Calculate the Value of nPr

#include 

#include 

void main(void)

{

   printf("%d\n", fact(8));

   int n, r; 

   clrscr();

   printf("Enter value for n and r\n");

   scanf("%d%d", &n, &r);

   int npr = fact(n) / fact(n - r);

   printf("\n Permutation values is = %d", npr);

}

int fact(int x)

{

   if (x <= 1)

       return 1;

   return x * fact(x - 1);

}

Output

40320

Enter value for n and r

5 4

Permutation values is = 120

Find the Sum of Series 1 + 1/2 + 1/3 + 1/4 + … + 1/N

#include 

#include 

void main()

{

    double number, sum = 0, i;

    clrscr();

    printf("\n enter the number ");

    scanf("%lf", &number);

    for (i = 1; i <= number; i++)

    {

        sum = sum + (1 / i);

        if (i == 1)

            printf("\n 1 +");

        else if (i == number)

            printf(" (1 / %lf)", i);

        else

            printf(" (1 / %lf) + ", i);

    }

    printf("\n The sum of the given series is %.2lf", sum);

}

Output

enter the number 4

1 + (1/2.000000) +  (1/3.000000) +  (1/4.000000)

The sum of the given series is 2.08

Find Sum of the Series 1/1! + 2/2! + 3/3! + ……1/N!

#include 

#include  

double sumseries(double);

main()

{

    double number,sum;

    printf("\n Enter the value:  ");

    scanf("%lf", &number);

    sum = sumseries(number);

    printf("\n Sum of the above series = %lf ", sum);

}

double sumseries(double m)

{

    double sum2 = 0, f = 1, i;

    for (i = 1; i <= m; i++)

    {

        f = f * i;

        sum2 = sum2 +(i / f);

    }

    return(sum2);

}

Output

Enter the value:  5

Sum of the above series = 2.708333